((1)/(n-4))+((2)/(n-2))=((2)/(n^2-6n+8))

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Solution for ((1)/(n-4))+((2)/(n-2))=((2)/(n^2-6n+8)) equation:



((1)/(n-4))+((2)/(n-2))=((2)/(n^2-6n+8))
We move all terms to the left:
((1)/(n-4))+((2)/(n-2))-(((2)/(n^2-6n+8)))=0
Domain of the equation: (n-4))!=0
n∈R
Domain of the equation: (n-2))!=0
n∈R
Domain of the equation: (n^2-6n+8)))!=0
n∈R
We calculate fractions

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